L09 / Three-phase AC circuits
Three-Phase AC Circuits II
Use per-phase equivalents to calculate three-phase power and reconcile source, line, and load.
01 / UNDERSTAND & PREDICT
Understand the model, then predict the result
- Distinguish phase/line voltage and branch/line current.
- Check √3 and 30° using voltage differences and terminal KCL.
- Check three-phase power and zero neutral current in a balanced set.
Sequence and reference
This module uses source VAN = Vphase∠0° relative to a reference neutral. In abc, B and C are −120° and +120°. Reversing sequence changes angles while retaining balanced-load total power.
Three-phase power
Sum source phase-voltage times line-current conjugates, or sum load branch powers. Balanced sinusoidal three-phase total instantaneous power is constant although each phase power oscillates.
Baseline example: check each step
- Y branch voltage = 400/√3 ≈ 230.940 V.
- Branch and line current ≈ 9.238 A; impedance angle ≈ 36.870°.
- P=5120 W, Q=3840 var, |S|=6400 VA.
- With the same branch impedance in Δ: branch current=16 A, line current≈27.713 A, P=15360 W.
Cross-check the original slides
02 / EXPLORE
Change one input and explain the response
Switch to Δ and multiply both impedance components by 3. Verify the original Y current and power return. Reverse sequence and inspect VAB phase.
Advanced parameters / test readings
Preparing the model.
Three phase voltages
Three line currents
Current intermediate values and numerical checks
The model uses an ideal balanced source, three identical impedances, and zero line impedance. The source neutral provides a phase reference; a delta load has no neutral conductor.
03 / EDIT & COMPUTE
Edit code to reproduce the model independently
Reproduce the baseline, then modify the parameter scan. The source contains reusable independent model functions; edit the current function and inspect numerical checks.
case is a snapshot of the controls when you press Run. Call solve(case) and assign the final solution to result to plot it.
The first run needs internet access to download Python. Computation stays in your browser; the solver uses only the standard library.
Ready to run.
Output appears here.
Last Python run and current control reference
Inspect and edit the model source (advanced)
Edit this module's function and run again. case.module selects the module; solve(case) returns values, plots, and checks. The parameter experiment keeps the original JavaScript reference for comparison.
04 / CHECK & EXPLAIN
Companion experiment practice and feedback
VLL=400 V RMS, abc sequence, Y branch Z=20+j15 Ω, VAN angle 0°.
Practice uses fixed baseline inputs independently of the controls. Each field displays its tolerance.
See the worked solution
- Y branch voltage = 400/√3 ≈ 230.940 V.
- Branch and line current ≈ 9.238 A; impedance angle ≈ 36.870°.
- P=5120 W, Q=3840 var, |S|=6400 VA.
- With the same branch impedance in Δ: branch current=16 A, line current≈27.713 A, P=15360 W.
Finally, explain in your own words
- What are the inputs, references, and main assumptions?
- Switch to Δ and multiply both impedance components by 3. Verify the original Y current and power return. Reverse sequence and inspect VAB phase.
- Did your code edit change physical parameters, the method, or representation bases? Which check helps identify that?
Passing numerical and understanding checks records this lecture’s companion practice as “practice checks passed.”
